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8x^2-15=4x^2-40
We move all terms to the left:
8x^2-15-(4x^2-40)=0
We get rid of parentheses
8x^2-4x^2+40-15=0
We add all the numbers together, and all the variables
4x^2+25=0
a = 4; b = 0; c = +25;
Δ = b2-4ac
Δ = 02-4·4·25
Δ = -400
Delta is less than zero, so there is no solution for the equation
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